Question

Help please!

A chemical reaction produces oxygen gas. You collect 3.00×10^23 oxygen gas molecules at STP .


What volume of oxygen gas did you collect?

Answer 1

To calculate the volume of collected oxygen gas, use Avogadro's number and the concept of molar volume at STP.

Step-by-step explanation:

To calculate the volume of oxygen gas collected, we can use the fact that one mole of a gas occupies 22.414 L at STP. Given that we collected 3.00x10^23 oxygen gas molecules at STP, we can calculate the number of moles using Avogadro's number (6.022x10^23 molecules/mol). From there, we can use the molar volume to find the volume of oxygen gas collected.

Answer 2

We colect 11.2 L of gas

Step-by-step explanation:

Let's apply the Ideal Gases Law to solve this:

P . V = n . R .T

where P and T in STP are 1 atm and 273°K

The thing is n which means the number of moles for the gas.

As we know, 1 mol of anything has 6.02x10²³ particles so

6.02x10²³ are occupied in 1 mol of gas

3.00x10²³ are occupied in (3.00x10² .1) / NA = 0.500 moles

So let's go to the formula:

1 atm . V = 0.500m . 0.082 . 273K

V = (0.500m . 0.082 . 273K) / 1atm

V = 11.2L

There is a rule, which says that 1 mol of gas in STP, occupies 22.4L so, since we have half a mole, it will occupy half the volume