Answer:
Δt ≈ 2.9137 ≈ 3 seconds per kilometer
Step-by-step explanation:
The speed of light is approximately 300000 km /s, while the speed fo the sound in the air is 0.3432 km/s.
The light takes therefore this time to travel one kilometer
![t = (x)/(v)](https://img.qammunity.org/2020/formulas/physics/high-school/o7hjilh5gu3f0h5qv1e9ewyzzhadznb6i2.png)
![t = (1)/(300000)](https://img.qammunity.org/2020/formulas/physics/high-school/i90zc0qfdxiqf5aih78tf6f8hfpa6hrm17.png)
![t = 3.33 x 10^(-6) s](https://img.qammunity.org/2020/formulas/physics/high-school/ctfha69v3mish4nil5kly2r0zg80nxxn4s.png)
On the other hand the sound takes this time to travel one kilometer
![t = (1)/(0.3432)](https://img.qammunity.org/2020/formulas/physics/high-school/2cq49r9hevu4e2m2xv47s9esh0htip3jz6.png)
t = 2.9137 s
Then the delay time is 2.9137 -
Δt ≈ 2.9137 ≈ 3 s