Answer:
(a) 14.7 mol
(b) -4.20 kJ
Step-by-step explanation:
First, we will find the initial moles of H₂ using the ideal gas equation.
P × V = n × R × T
16.0 atm × 30.0 L = n × (0.08206 atm.L/mol.K) × 298 K
n = 19.6 mol
The moles of H₂ after the reaction are:
P × V = n × R × T
4.0 atm × 30.0 L = n × (0.08206 atm.L/mol.K) × 298 K
n = 4.9 mol
The moles of H₂ that reacted are 19.6 mol - 4.9 mol = 14.7 mol
The heat of combustion for H₂ is -286 kJ/mol. The amount of heat released when 14.7 moles of H₂ are burned is:
14.7 mol × (-286 kJ/mol) = -4.20 × 10³ J = -4.20 kJ