Question

If f(x) = x2 − 6x + 19, complete the square and determine the minimum or maximum value of the function.

A) f(x) = (x + 3)2 + 28 and f(x) has a maximum value f(3) = 28.
B) f(x) = (x + 3)2 + 28 and f(x) has a minimum value f(3) = 28.
C) f(x) = (x − 3)2 + 10 and f(x) has a maximum value f(3) = 10.
D) f(x) = (x − 3)2 + 10 and f(x) has a minimum value f(3) = 10. Eliminate

Answer 1

D

Explanation:

(Using the formula in my attachment)

x^2 − 6x + 19

(x - 3)^2 = x^2 - 6x + 9

9 - e = 19

e = -10

(x - 3)^2 - e

(x - 3)^2 - - 10

(x - 3)^2 + 10

when x - 3 = 0, x = 3

Subsitute 3 into the equation

(3 - 3)^2 + 10

0 + 10

Minimum (3,10) in this case f(3) = 10