Answer:
t = 2.2 [days] and is there is a round trip, it will be double time t = 4.4 [days]
Step-by-step explanation:
First, we need to arrange the problem to work in the same unit system (SI).
We need to convert the 1800 [miles] to meters, therefore:
![1800[miles] * (1609.34[m])/(1[mile]) }=2896812[m] = 2896.8[km]](https://img.qammunity.org/2020/formulas/physics/middle-school/dh38s8xti9rh1zhx2eby5fo6kjtzv5aeir.png)
Now using the following equation of kinematics, for the avarage velocity we have:
![v=(x)/(t) \\where \\v=velocity [m/s]\\t = time [s]\\x=distance traveled [m]\\](https://img.qammunity.org/2020/formulas/physics/middle-school/efv8iiphgh0yvjzxvnl5j7n4yh0j36fbev.png)
therefore:
![t=(x)/(v) \\t=(2896812)/(15)\\ t=193120.8[s]](https://img.qammunity.org/2020/formulas/physics/middle-school/upb1ncnu7doft0nycbp4gao0g7zba3uu66.png)
Now we can convert from seconds into days.
![193120.8[s]*(1[hr])/(3600[s])*(1[day])/(24[hr])\\ t = 2.2[days]](https://img.qammunity.org/2020/formulas/physics/middle-school/dzmpks2zk7cyjzv1qaqd27j1xx5tbswgd1.png)
Now if the truck has the need to come back, the team will spend double time.
t= 4.4 [days]