Question

Determine the voltage across a 2000 pF capacitor that is storing 20 microcouloms (20 µC) of charge.

Answer 1

V= 10,000 V

Step-by-step explanation:

Capacitance= C= 2000 pF

Charge = q = 20 μC

Relationship between voltage, charge and capacitance of a capacitor is:

Q= CV

⇒ V = Q/C

⇒ V= 20*
`10^(-6)`/
`2000*10^(-12 )`

⇒ V= 10,000 V