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4 votes
Identify the vertex for
f(x)=4x^2-8x-4

User IMSoP
by
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1 Answer

7 votes

Answer:

Explanation:

You could complete the square to do this, or you could just evaluate the h coordinate using the simple formula


h=-(b)/(2a)

then find k by subbing that h value into the equation for x to find y which is the same as k. In our quadratic, a = 4, b = -8, and c = -4.


h=(-(-8))/(2(4))=1

Now sub that value into the quadratic to find y (k):


4(1)^2-8(1)-4=4-8-4=-8

The vertex of the quadratic is (1, -8)

User Laffoyb
by
8.1k points