Question

Kelli weighs 425 N, and she is sitting on a playground swing that hangs 0.36 m above the ground. Her mom pulls the swing back and releases it when the seat is 1.00 m above the ground. Assume that air resistance is negligible. (a) How fast is Kelli moving when the swing passes through its lowest position?

Answer 1

V = 3.54 m/s

Step-by-step explanation:

Using the conservation of energy:

`E_i = E_f`

so:

`wh = (1)/(2)mV^2`

where w is te weigh of kelly, h the distance that kelly decends, m is the mass of kelly and V the velocity in the lowest position.

So, the mass of kelly is:

m = 425N/9.8 = 43.36 Kg

and h is:

h = 1m-0.36m =0.64m

then, replacing values, we get:

`(425N)(0.64m) = (1)/(2)(43.36kg)v^2`

Solving for v:

V = 3.54 m/s