Answer:
The 10th term from the end of the AP is 39 th term

Explanation:
Given:
Arithmetic Sequence as
7 , 10 , 13........154,157
∴ First term = a₁ = 7
Second term = a₂ = 10
∴ Common Difference = d = a₂ - a₁ = 10 - 7 = 3
∴ d = 3
To Find:
Solution:
An equation for the nth term of the arithmetic sequence is given by
Substituting a₁ and d and we get

There are 49 terms in given AP
Therefore the 10th term from the end will be 39th term
