Question

Firefighters are holding a nozzle at the end of a hose while trying to extinguish a fire. The nozzle exit diameter is 8 cm, and the water flow rate is 16 m3/min. Take the density of water as 1000 kg/m3 and the momentum-flux correction factor as unity.

Answer 1

Question

Determine the average water exit velocity

Answer:

53.05 m/s

Step-by-step explanation:

Given information

Volume flow rate,
`Q=16 m^(3)/min`

Diameter d= 8cm= 0.08 m

Assumptions

• The flow is jet flow hence momentum-flux correction factor is unity
• Gravitational force is not considered
• The flow is steady, frictionless and incompressible
• Water is discharged to the atmosphere hence pressure is ignored

We know that Q=AV and making v the subject then

`V=\frac {Q}{A}` where V is the exit velocity and A is area

Area,
where d is the diameter

By substitution

`V=\frac {16* 4}{\pi 0.08^(2)}=3183.098862 m/min`

To convert v to m/s from m/s, we simply divide it by 60 hence

`V=\frac {3183.098862  m/min}{60 s}=53.0516477 m/s\approx 53.05 m/s`