According to the general equation for conditional probability, if P(ANB) = 3/10 and P(B)= 3/5, then P(A I B) is
![(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ybjkeso7qr5r7js5h0mv9de35dih0sxfpl.png)
Solution:
Given that, According to the general equation for conditional probability,
![P( A \cap B) = (3)/(10)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/akpaow50fxavlhawmf6elvrqtcqqqxhiyg.png)
![P(B) = (3)/(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qftbn6xgow1747qp9p3s70vtpqpcynbkwm.png)
We need to find
![P(A | B)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/z1ldham22kvh0ix8iqhbq2zzcq6j4b640q.png)
The required formula is:
![P(A | B)=(P(A\cap B))/(P(B))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/e69r86oavatua93a8lr3lg2ncefukz4mig.png)
Substituting the values,
![\begin{aligned}&P(A | B)=((3)/(10))/((3)/(5))\\\\&P(A | B)=(3)/(10) * (5)/(3)=(1)/(2)\end{aligned}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t9flv9bblkblyhne6mbyxy8hbhdbx04v6r.png)
![\text{ Thus } P(A | B) = (1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/p5gt437jkya8p2tr5q4c3y9etzzvspds6e.png)