Question

The naturally occurring isotopes of vanadium are vanadium-50 and vanadium-51. Vanadium-50 has an abundance of 0.250% and a mass of 49.947 amu. Vanadium-51 has an abundance of 99.750% and a mass of 50.944 amu. Calculate the average atomic mass of vanadium.

A) 50.942 amu
B) 62.558 amu
C) 63.303 amu
D) 5094.151 amu

Answer 1

The answer to your question is letter A

Step-by-step explanation:

Abundance Atomic mass

V-50 0.25% 49.947

V-51 99.750% 50.944

Formula

Average atomic mass = [V-50-Abundance x V-50-Atomic mass] +

[ V-51-Abundance x V-51-Atomic mass]

Substitution

Average atomic mass = [ 0.0025 x 49.947] + [0.9975 x 50.944]

= 0.125 + 50.817

Result

= 50.942 amu