Question

Given matrix A below, and that A = B, find the value of the elements in B. A = 9 −2 3 2 17 0 3 22 8 b11 = b12 = b13 = b21 = b22 = b23 = b31 = b32 = b33 =

Answer 1

`b_(11)=9,b_(12)=-2,b_(13)=3,b_(21)=2,b_(22)=17,b_(23)=0,b_(31)=3,b_(32)=22,b_(33)=8`

Explanation:

Consider the given matrix

`A=\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]`

Let matrix B is

`B=\left[\begin{array}{ccc}b_(11)&b_(12)&b_(13)\\b_(21)&b_(22)&b_(23)\\b_(31)&b_(32)&b_(33)\end{array}\right]`

It is given that

`A=B`

`\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]=\left[\begin{array}{ccc}b_(11)&b_(12)&b_(13)\\b_(21)&b_(22)&b_(23)\\b_(31)&b_(32)&b_(33)\end{array}\right]`

On comparing corresponding elements of both matrices, we get

`b_(11)=9,b_(12)=-2,b_(13)=3`

`b_(21)=2,b_(22)=17,b_(23)=0`

`b_(31)=3,b_(32)=22,b_(33)=8`

Therefore, the required values are
`b_(11)=9,b_(12)=-2,b_(13)=3,b_(21)=2,b_(22)=17,b_(23)=0,b_(31)=3,b_(32)=22,b_(33)=8`.