Answer:
The value of A =
The value of B =
The value of C =
The value of D =
Explanation:
Given as :
The following relations are as
=4 A ...........1
d = 20 B ...........2
d =
C ...........3
And d =
![(5)/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/71m7ycwqsajk7vn8bqlt1ri7kfsbo06xti.png)
Now, From the above relations
Put the value of d in eq 1
∵ 4 A =
![(d)/(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4muc3aga7s8ee656u9784kit6lzl3kenqr.png)
So, d = 5 × 4 A
Or,
= 20 A
∴ A =
=
I.e The value of A =
Again
From eq 2
∵ d = 20 B
Put the value of d
So,
= 20 B
Or, B =
![((5)/(4))/(20)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9dfp3uj9fpwuv7td1e5qwufuuddvf1wyz8.png)
∴ B =
I.e The value of B =
Similarly
From eq 3
d =
C
Put the value of d
So,
=
C
Or, C =
![(5* 5)/(4* 4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jqej6jdyixmtnyc0bpg1kts2tu0pzwremq.png)
∴ C =
I.e The value of C =
Hence The value are
The value of A =
The value of B =
The value of C =
The value of D =
Answer