Answer:
Mass of CO₂ = 0.352 g
Step-by-step explanation:
Given data:
Volume of C₄H₁₀ = 36.0 mL(36/1000 =0.036 L)
Temperature = 273 K
Pressure = 1 atm
Mass of carbon dioxide produced = ?
Solution:
Chemical equation:
2C₄H₁₀ + 13O₂ → 10H₂O + 8CO₂
Number of moles of C₄H₁₀ :
PV = nRT
n = PV/RT
n = 1 atm × 0.036 L / 0.0821 atm. L / mol. K × 273 k
n = 0.036 atm. L / 22.4 atm. L / mol
n = 0.002 mol
C₄H₁₀ : CO₂
2 : 8
0.002 : 8/2×0.002 = 0.008 mol
Mass of CO₂:
Mass = number of moles × molar mass
Mass = 0.008 mol × 44 g/mol
Mass = 0.352 g