Question is Incomplete, Complete question is given below;
Fiona wrote the linear equation y = 2/5 X -5. When Henry wrote his equation they discovered that his equation had all the same Solutions as fionas. which equation could have been Henry's.
A. X- 5/4y =25/4
B. X-5/2y=25/4
C. X-5/4y =25/4
D. X- 5/2y=25/2
Answer:
D.
![x- (5)/(2) y=(25)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/3b7txtbl3toz905w70nb2c9k6dbbekaakz.png)
Explanation:
Given:
Fiona's equation =
![y = (2)/(5)x-5](https://img.qammunity.org/2020/formulas/mathematics/high-school/edzwjfr7hllvgo84hcp7dc6yu5o5p7l2di.png)
We have to figure out which of the choices equals the equation given,
![y = (2)/(5)x-5](https://img.qammunity.org/2020/formulas/mathematics/high-school/edzwjfr7hllvgo84hcp7dc6yu5o5p7l2di.png)
Now we could solve each of the answer choices for
, but since each choice is in the format
, we can put the given equation in that format too.
![y = (2)/(5)x-5\\\\5 = (2)/(5)x -y\\\\(2)/(5)x -y= 5](https://img.qammunity.org/2020/formulas/mathematics/high-school/wpfv2y91q88lb513j54in9dpt8ny8uahdl.png)
Now in given choices x doesn't have any terms with it.
Hence we will make x term as 1 by dividing 5/2 on both side we get;
![((5)/(2) )(2)/(5)x -(5)/(2) y=5* (5)/(2) \\\\x-(5)/(2) y=(25)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/kly37cxzunfjs0jfx476d7unezb2am48zy.png)
Hence Henry equation will be
.