Answer:
0.690 liters is the volume of hydrogen gas produced if 2.00 grams of zinc is used with an excess of hydrochloric acid.
Step-by-step explanation:

Mole so zinc =

According to reaction, 1 mole of zinc gives 1 mole of hydrogen gas.
Then 0.03077 mole of zinc will give :
of hydrogen gas
Pressure of hydrogen gas ,P= 1 atm
Temperature of of hydrogen gas ,T= 273.15 K
Volume of hydrogen gas = V = ?
Moles of hydrogen gas = 0.03077 mol
PV = nRT (Ideal gas equation )

V = 0.690 L
0.690 liters is the volume of hydrogen gas produced if 2.00 grams of zinc is used with an excess of hydrochloric acid.