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4nh3 + 5o2 -- 4no + 6h2o how many moles of oxygen gas are needed to react with 23 moles of ammonia

User Veeman
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1 Answer

3 votes

Answer:

28.75 moles

Step-by-step explanation:

Data Given:

no. of moles of ammonia (NH₃) = 23 moles

no. of moles of oxygen gas (O₂) = ?

Reaction given

4NH₃ + 5O₂ -----------> 4NO + 6H₂O

Solution:

First we have to look at the reaction for moles details

4NH₃ + 5O₂ -----------> 4NO + 6H₂O

4 mol 5 mol

So,

if 4 moles of ammonia (NH₃) react with 5 moles of oxygen gas (O₂) so how many moles of oxygen gas (O₂) will be react with 23 moles of ammonia (NH₃).

Apply Unity Formula

4 moles of NH₃ ≅ 5 moles of O₂

23 moles of NH₃ ≅ X moles of O₂

Do cross multiply

moles of O₂ = 5 mol x 23 mol / 4 mol

moles of O₂ = 28.75 mol

So the no. of moles of O₂ that react with 23 moles of NH₃ = 28.75 mol

User Antstud
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