Answer:
Step-by-step explanation:
According to question
tan θ = y / x
Differentiate with respect to t on both the sides
![Sec^(2)\theta * (d\theta )/(dt)=(x* dy/dt-y* dx/dt)/(x^(2))](https://img.qammunity.org/2020/formulas/physics/high-school/za0jr2x73jehm1etyzuzugiak5ossbr1x0.png)
.... (1)
According to question,
tan θ = 5 / 9
So, Sec θ = 10.3 / 9 = 1.14
dx/dt = 9 units/s
dy/dt = 19 units/s
Substitute the values in equation (1), we get
![(d\theta )/(dt)=(9* 19-5* 9)/(81* 1.14^(2))](https://img.qammunity.org/2020/formulas/physics/high-school/f74zb8l5rmqfz8uxfptlst2839d8q97q1m.png)
dθ/dt = 1.2 units/s