199k views
0 votes
Let θ (in radians) be an acute angle in a right triangle and let x and y, respectively, be the lengths of the sides adjacent to and opposite θ. Suppose also that x and y vary with time. At a certain instant x=9 units and is increasing at 9 unit/s, while y=5 and is decreasing at 19 units/s. How fast is θ changing at that instant?

User Timmz
by
5.9k points

1 Answer

5 votes

Answer:

Step-by-step explanation:

According to question

tan θ = y / x

Differentiate with respect to t on both the sides


Sec^(2)\theta * (d\theta )/(dt)=(x* dy/dt-y* dx/dt)/(x^(2))


(d\theta )/(dt)=(x* dy/dt-y* dx/dt)/(x^(2)* Sec^(2)\theta) .... (1)

According to question,

tan θ = 5 / 9

So, Sec θ = 10.3 / 9 = 1.14

dx/dt = 9 units/s

dy/dt = 19 units/s

Substitute the values in equation (1), we get


(d\theta )/(dt)=(9* 19-5* 9)/(81* 1.14^(2))

dθ/dt = 1.2 units/s

User GSD
by
6.1k points