Question

A car travelling at 32 m/s decelerates at a rate of 6 m/s ^ 2 over 4 secondsWhat is the final velocity the car

Answer 1

v=8m/s

Step-by-step explanation

The initial velocity, u, of the car=32m/s

Since the car has decelerated, we negate the acceleration

This implies that,

`a=-6m{s}^( -2)`

Time,t=4s

Let v be the final velocity,

using the relation,

`a = (v - u)/(t)`

We obtain the below by substitution

`- 6= (v - 32)/(4)`

By cross multiplying we obtain,

`- 6 * 4 = v - 32`

`- 24=v-32`

`- 24+32=v`

v=8m/s