Question

What will be the displacement of a train moving from an initial velocity of 12 m/ s to a final velocity of 26 m/s in 14 seconds ?

Answer 1

266 m

Step-by-step explanation:

We are given;

• Initial velocity, u = 12 m/s
• Final velocity, v = 26 m/s
• Time, t = 14 seconds

We are required to calculate the displacement;

• We are going to use the appropriate equation of linear motion;
• The appropriate linear motion equation is;

S = 0.5(u +v)t

Where, S is the displacement

• Therefore;

S = 0.5(12 m/s + 26 m/s)14 seconds

= 266 m

Thus, the displacement of the train is 266 m