Question

On a coordinate plane, a line goes through (negative 3, 2) and (2, negative 1). A point is at (3, 0). What is the equation of the line that is perpendicular to the given line and passes through the point (3, 0)

Answer 1

y=\frac{5}{3}x-5

Explanation:

Answer 2

Answer:
`y=(5)/(3)x-5`

Explanation:

Alright, lets get started.

Two points are given as (-3,2) and (2,-1)

Slope will be :
`(y_(2)-y_(1))/(x_(2)-x_(1))`

Slope will be :
`(-1-2)/(2-(-3))`

Slope will be :
`(-3)/(5)`

Our line is perpendicular to this slope, then,

`m * ((-3)/(5)) =-1`

`m=(5)/(3)`

Line passing through the point (3,0) and having slope
`(5)/(3)`, is given by :

`y-y_(1)=m(x-x_(1) )`

`y-0=(5)/(3)(x-3)`

`y=(5)/(3)x-5` : Answer

Hope it will help :)