Answer:
This question can be answered by using conversation of energy.
![K_1 + U_1 = K_2 + U_2](https://img.qammunity.org/2020/formulas/physics/college/2cffzfbz8tj69a9zwrsf6f9wz8yy0lu0ot.png)
![(1)/(2)mv_(0)^2 + mgh_1 = 0 + mgh_2](https://img.qammunity.org/2020/formulas/physics/college/v4k04yuur1poiinmicqm9is711c35elgqc.png)
![(1)/(2)(3)v_0^2 + (3)(9.8)(30) = (3)(9.8)(45)\\(1)/(2)(3)v_0^2 = 441\\v_0^2 = 294\\v_0 = 17.14 m/s](https://img.qammunity.org/2020/formulas/physics/college/yn1i5f2o1t1gg2v4y1txzw0h2l6nps856a.png)
Step-by-step explanation:
Note that we take
because we are looking for the minimum initial speed for the penguin to reach the top of the second hill. Any other speed more than this will already be enough for him.