Answer:
Explanation:
Given that a box ontains three cards, labeled 1, 2, and 3.
Two cards are chosen at random, with the first card being replaced before the second card is drawn.
Let X represent the number on the first card, and let Y represent the number on the second card.
Since drawing is done with replacement, we find that X and Y are independnet
A) Joint pdf of x and y are
y x 0 1 2 3 Total
0 0.0625 0.0625 0.0625 0.0625 0.25
1 0.0625 0.0625 0.0625 0.0625 0.25
2 0.0625 0.0625 0.0625 0.0625 0.25
3 0.0625 0.0625 0.0625 0.0625 0.25
Total 0.25 0.25 0.25 0.25
B) Pdf of X is
x 0 1 2 3
p 0.25 0.25 0.25 0.25
and Y also will have same pdf
C)
![\mu_x = 0.25(0+1+2+3) = 1.5\\\mu_y = 0.25(0+1+2+3) = 1.5](https://img.qammunity.org/2020/formulas/mathematics/college/jorx41c599hl76he81q0l1nv6v584y0di5.png)
D)
![\mu_(xy ) =E(x) E(y) = 2.25](https://img.qammunity.org/2020/formulas/mathematics/college/d292xu06i70ril6yct9udclds21if359i0.png)
E) Cov (x,y) =0 since X and Y are independent