Question

What is the equation the line that passes through the points (2,4) and (4,0)

Answer 1

The equation of the line is 2 x + y = 8.

Explanation:

Here the given points are ( 2, 4) & ( 4, 0)

Equation of a line whose points are given such that

(
`x_(1), y_(1)` ) & (
`x_(2), y_(2)` )-

y -
`y_(1)` =
`( y_(2) - y_(1) )/( x_(2) - x_(1) )` ( x -
`x_(1)` )

i.e. y - 4 =
`(0 - 4)/(4 - 2)` ( x- 2)

y - 4 =
`(- 4)/(2)` ( x - 2 )

y - 4 = - 2 ( x - 2 )

y - 4 = - 2 x + 4

2 x + y = 8

Hence the equation of the required line whose passes trough the points ( 2, 4) & ( 4, 0) is 2 x + y = 8.