Answer:
a) v = 160.9 Km / h, b) K = 9,988 10⁵ J , c) d = 335.2 m , d) a = - 2.9796 m / s²
Step-by-step explanation:
a) The average speed is defined as the distance traveled in the time interval
v = d / t
Let's reduce the magnitudes to the SI system
t = 30 min (60 s / 1min) = 1800 s
d = 50 mile (1609 m / 1mile) = 80450 m
v = 80450/1800
v = 44.6944 m / s
v = 44.6944 m / s (1 km / 1000m) (3600 s / 1h)
v = 160.9 Km / h
b) W = 2 ton (1000 kg / 1 ton) = 1000 kg
K = ½ m v²
K = ½ 1000 44.694²
K = 9,988 10⁵ J
c) take t = 15 s to stop
v = v₀ - at
v = 0
a = v₀ / t
a = 44,694 / 15
a = 2.9796 m / s²
v² = v₀² - 2 a d
v = 0
d = v₀² / 2 a
d = 44.694² / (2 2.9796)
d = 335.2 m
d) the average acceleration is the change of speed in the time interval
a = (v - v₀) / (t -t₀)
a = (0 - 44.694) / 15
a = - 2.9796 m / s²