The price of 1 youth ticket is $ 22
Solution:
Let "y" be the price of 1 youth ticket
Let "a" be the price of 1 adult ticket
To find: price of 1 youth ticket
Brianna's family spent $134 on 2 adult tickets and 3 youth tickets at an amusement park
So we can frame a equation as:
2 adult tickets x price of 1 adult ticket + 3 youth tickets x price of 1 youth ticket = 134
![2 * a + 3 * y = 134](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8o42glyr8ihvo8dp930rol5gyq0a8q44jx.png)
2a + 3y = 134 ---- eqn 1
Max's family spent $146 on 3 adults tickets and 2 youth tickets
So we can frame a equation as:
3 adult tickets x price of 1 adult ticket + 2 youth tickets x price of 1 youth ticket = 146
![3 * a + 2 * y = 146](https://img.qammunity.org/2020/formulas/mathematics/middle-school/are1c0r9msqk6b73coa1wir0zs7ee24du1.png)
3a + 2y = 146 ----- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "y"
Multiply eqn 1 by 3
6a + 9y = 402 ---- eqn 3
Multiply eqn 2 by 2
6a + 4y = 292 ----- eqn 4
Subtract eqn 4 from eqn 3
6a + 9y = 402
6a + 4y = 292
( - ) -------------------
5y = 110
y = 22
Thus the price of 1 youth ticket is $ 22