Question

To what pressure would you have to compress 48.0 L

of oxygen gas at 99.3 kPa in order to reduce its vol-
ume to 16.0 L?

Answer 1

298 kPa

Step-by-step explanation:

Data Given:

initial Volume of oxygen V1= 48.0 L

Final Volume of oxygen V2= 16.0 L

initial pressure of oxygen P1= 99.3 kPa

initial Pressure of oxygen P2= ?

Solution:

The Boyle's law formula will be applicable here at constant temperature

Boyle's law formula

P1V1 = P2V2

As we have to find final pressure so rearrange the equation

P2 = P1V1 /V2 ....................(1)

Put values in Equation 1

P2 = 99.3 kPa x 48 L /16 L

P2 = 298 kPa

So the final pressure will be 298 kPa