Answer:
Step-by-step explanation:
Let q be the charges on each spheres , 2d be the distance between them in equilibrium , T be tension in the string and F be the force of repulsion between them
F = k q² /4d²
For equilibrium
T sin15 = F
T cos 15 = mg
tan15 = F / mg
F = mg tan15
k q² /4d² = mg tan15
k q² = 4d² x mg tan15
= 4 x( .7 sin15)² x 3.1 x 10⁻³ x 9.8 x .2679
= 1.068 x 10⁻³
q = .3444 x 10⁻⁶ C
no of electrons
= .3444 x 10⁻⁶ / 1.6 x 10⁻¹⁹
= 215.25 x 10¹⁰