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1 vote
A vector points -1.55 units along the x-axis and 3.22 units along the y-axis what is the magnitude of the vector

2 Answers

2 votes

Answer:

The magnitude of the vector is 3.57 units.

Step-by-step explanation:

The x component of the vector,
v_x=-1.55\ \text{units}

The y component of the vector is
v_y=3.22\ \text{units}

We need to find the magnitude of the vector. We know that the magnitude of the vector is given by :


v=√(v_x^2+v_y^2)


v=√((-1.55)^2+(3.22)^2)


v=3.57\ \text{units}

So, the magnitude of the vector is 3.57 units. Hence, this is the required solution.

User Anish Mittal
by
5.0k points
1 vote

Answer:

3.57 units

Step-by-step explanation:


x =√( (-1.55)^2+(3.22)^2) = 3.57 units

User Karhgath
by
5.8k points