A bag contains one red one yellow one blue and one green marble what is the probability of choosing a green marble not replacing it and then choosing a red marble

Question

asked Jun 26, 2020 121k views

2 Answers

Madusanka · Answer 1 · 2020-06-30T20:52:44+0000

The total probability of choosing a green marble not replacing it and then choosing a red marble is
(1)/(12)

Solution:

Given that bag contains one red one yellow one blue and one green marble

To find: Probability of choosing a green marble not replacing it and then choosing a red marble

The probability of an event is given as:

$\text{ probability } =\frac{\text { number of favorable outcomes }}{\text { total number of possible outcomes }}$$

Here total number of possible outcomes = 1 red + 1 yellow + 1 blue + 1 green

total number of possible outcomes = 4 marbles

Here favourable outcome is choosing a green marble not replacing it and then choosing a red marble

Let us first find probability of choosing a green marble

Favorable outcome = green marble

Number of favorable outcomes = 1

probability = (1)/(4)

Now without replacing, we have to choose a red marble

Without replacing means, green marble is not considered

So total number of possible outcomes = 4 - 1 = 3

probability = (1)/(3)

The total probability of choosing a green marble not replacing it and then choosing a red marble:

$\rightarrow (1)/(4) * (1)/(3) = (1)/(12)$

So the required probability is
(1)/(12)