Question

A bag contains one red one yellow one blue and one green marble what is the probability of choosing a green marble not replacing it and then choosing a red marble

Answer 1

Answer:B) 1/12♡

Explanation:

Answer 2

The total probability of choosing a green marble not replacing it and then choosing a red marble is
`(1)/(12)`

Solution:

Given that bag contains one red one yellow one blue and one green marble

To find: Probability of choosing a green marble not replacing it and then choosing a red marble

The probability of an event is given as:

`\text{ probability } =\frac{\text { number of favorable outcomes }}{\text { total number of possible outcomes }}$`

Here total number of possible outcomes = 1 red + 1 yellow + 1 blue + 1 green

total number of possible outcomes = 4 marbles

Here favourable outcome is choosing a green marble not replacing it and then choosing a red marble

Let us first find probability of choosing a green marble

Favorable outcome = green marble

Number of favorable outcomes = 1

`probability = (1)/(4)`

Now without replacing, we have to choose a red marble

Without replacing means, green marble is not considered

So total number of possible outcomes = 4 - 1 = 3

`probability = (1)/(3)`

The total probability of choosing a green marble not replacing it and then choosing a red marble:

`\rightarrow (1)/(4) * (1)/(3) = (1)/(12)`

So the required probability is
`(1)/(12)`