Answer:
4820.9 J of work is done on the flight bag.
Step-by-step explanation:
Given:
Force acting on the bag is,
![F=30.0\ N](https://img.qammunity.org/2020/formulas/physics/high-school/3naose7lnfg0gs11hht0u4lnlx29mdr51q.png)
Displacement of the bag caused by the force is,
![S=250.0\ m](https://img.qammunity.org/2020/formulas/physics/high-school/3jxmo212ob68ky0cuyrizxj740sn4qn9m6.png)
Angle between the direction of force and direction of displacement caused is,
![\theta = 50\°](https://img.qammunity.org/2020/formulas/physics/high-school/70jgp84s47bum8ihlge64fgzo85dpwtetn.png)
Now, the formula to calculate work done on a body by a force 'F' causing displacement 'S' at an angle
between the two vectors is given as:
![W=FS\cos \theta](https://img.qammunity.org/2020/formulas/physics/high-school/jtkkp2xe1k1797tksiamnuaxbmjo5cdgw2.png)
Plug in the given values and solve for work done 'W'. This gives,
![W=(30.0\ N)(250.0\ m)(\cos 50)\\W=4820.9 \textrm{ N-m or 4820.9 J}](https://img.qammunity.org/2020/formulas/physics/high-school/b49wkuq0f5q9x1un2nz8l0rvsvgqey1fmh.png)
Therefore, the work done on the flight bag is 4820.9 J.