Question

When a pitcher throws a baseball, it reaches a top speed of 45 m/s. If the

baseball takes 0.9 seconds to travel from the pitcher to the catcher, what is
its acceleration? (Assume the ball is moving at 0 m/s right before it leaves
the pitcher's hand.)



A. 45 m/s2

B. 50 m/s2


C. 55m/s 2


D. 40 m/s2

Answer 1

B. 50 m/s²

Step-by-step explanation:

Given:

Initial velocity of the ball is,
`u=0\ m/s`

Final velocity of the ball is,
`v=45\ m/s`

Time taken by the ball is,
`t=0.9\ s`

Acceleration is defined as the rate of change of velocity. So, the velocity of the ball is changing with time. So, acceleration is given as:

`a=(v-u)/(t)`

Plug in 0 for 'u', 45 for 'v', 0.9 for 't' and solve for acceleration, 'a'. This gives,

`a=(45-0)/(0.9)\\\\a=(45)/(0.9)\\\\a=50\ m/s^2`

Therefore, the acceleration of the ball is 50 m/s².