Question

A

HIGHLIGHT
CLEAR HIGHLIGHT
CALCULATOR
24. A blacksmith swings a 3.0-kg hammer at 1.5 m/s. He hits a 25.0-kg anvil and the hammer bounces up 0.08 m. The energy change for the hammer was ---

Answer 1

The change in energy is 1.023 J.

Step-by-step explanation:

The formula for Kinetic Energy is
`(1)/(2) mv^(2)`

The formula for Potential Energy is
`mgh`

In the above question, the hammer has an initial Kinetic Energy which hits the anvil loses some energy and rises up to gain potential energy.

Initial Kinetic Energy=
`(1)/(2) * 3 * 1.5^(2)`

=3.375 J

Potential Energy it gains after rising the particular height= 3*9.8*0.08

=2.352 J

Therefore, the difference in energy is 1.023 J.