Question

COO

1. ABCD is a parallelogram. The diagram is not drawn to scale. If mZCDA = 125°, then mZDCB
(1 point)
m
mm
125°
65°
55°
120°

Answer 1

Therefore

m∠ DCB is 55°

Explanation:

Given:

ABCD is a parallelogram. The diagram is not drawn to scale.

m∠CDA = 125°,

To FInd

m∠DCB = ?

Solution:

ABCD is a parallelogram.

AD || BC .......{opposite sides of a parallelogram are parallel}

∴∠CDA+∠DCB = 180°{SUM of the interior angles between parallel are supplementary}

substituting the values we get

`125+m\angle DCB=180\\\\m\angle DCB =180-125=55\\\\m\angle DCB =55\°`

Therefore

m∠ DCB is 55°