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Two water balloons of mass 0.35 kg collide and bounce off of each other

without breaking. Before the collision, one water balloon moved at a velocity
of 2.5 m/s east, while the other moved at a velocity of 2.25 m/s west. After
the collision, one balloon moves at a velocity of 1.75 m/s west. What is the
velocity of the other water balloon?
O
A. 2 m/s west
O
B. 0.25 m/s east
O
C. 0.25 m/s west
O
D. 2 m/s east

User Dethos
by
5.1k points

2 Answers

2 votes

Answer:

2 m/s east

just did it ;D

Step-by-step explanation:

User Tywanna
by
5.9k points
5 votes

Answer:

Option D

2 m/s East

Step-by-step explanation:

From the law of conservation of momentum, the sum of initial momentum equals the sum of final momentum

Momentum, p=mv where m is the mass and v is the velocity

Since the masses are the same then


m(u_1+u_2)=m(v_1+v_2)

Therefore


u_1+u_2=v_1+v_2

where
v_1 and
v_2 are final velocities of objects while
u_1 and
u_2 are the initial velocities respectively

Taking East direction as positive then West as negative and by substitution


2.5+-2.25=v_1-1.75

Therefore


v_1=2 m/s hence East since it's positive

User SRR
by
5.5k points