Answer:
3x ≥ 2 + 2x
Explanation:
Given:
![x\geq 2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pkeerpz7bvnrn8na6qptov6qo1bo8127oe.png)
Solution:
Now, we have to write an inequality with x on both sides whose solution is x is greater than or equal to 2.
![x\geq 2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pkeerpz7bvnrn8na6qptov6qo1bo8127oe.png)
Now we add 2x on both side.
![x + 2x\geq 2 + 2x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9f8zzoifyncwjd5sfsvrwn0vq3ggvtsdye.png)
![3x\geq 2 + 2x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yfch70ocxefsfokg641do2g7qutwgzkdgo.png)
Therefore, the inequality which has a solution x ≥ 2 is:
3x ≥ 2 + 2x