Answer:
![radius=5\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kpcgulhjmih2d8t8qqrfpp9ync00u43679.png)
Explanation:
Let r be the radius of the circle and A be the area of the circle.
Given:
![r_(1) = 2\ cm, A_(1)=12.566\ cm^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ttud66kuzdzjwj2nltrar1pvd0m3pqm9cp.png)
And
![r_(2) = ?, A_(2)=78.54\ cm^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k2eaklqqp4e8k19d85u19ejtlz0x3q4mhw.png)
The area of a circle is directly proportional to the square of its radius.
A ∝
![r^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ngb5kfslswssdh87u5qlkzllv6wbf93140.png)
-----------(1)
Where k is the constant of proportionality
Find constant value by substituting
![r_(1) = 2\ cm, A_(1)=12.566\ cm^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ttud66kuzdzjwj2nltrar1pvd0m3pqm9cp.png)
in equation 1.
![A = kr^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vxam97dwyuklauimi1dhwfkp304xn6otct.png)
![A_(1)=k(r_(1))^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7843zzidoxgohq66v6ixrc49zjpn7abq4o.png)
![12.566=k* 2^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4q0b5dcudgrpr6dza13tp52he2oes8ggb7.png)
![12.566=k* 4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/beayehss68mo15pjdry0mpud3tobb3c6h6.png)
![k=(12.566)/(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jaac0pi5rnywlrjtv65aewjsa3i7ktnfwp.png)
![k=3.141](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pmh9unao0vcbzixi7zoxd3v9sp3vbxsut4.png)
Find
by substituting k and
value in equation 1.
![A = kr^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vxam97dwyuklauimi1dhwfkp304xn6otct.png)
![A_(2)=k(r_(2))^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mvcli9wl5yg24192b5rs7qrw1rpj00y06h.png)
![12.566=3.141* (r_(2))^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7q44o8mo28bhdh0z9sfa3n7w7x4d6rlbjb.png)
![(r_(2))^(2)=(78.54)/(3.141)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/neyfne4u3h71s87c436kfj7gwoq5rwqppx.png)
![(r_(2))^(2)=25.004](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ex5dkd7gmqfljsp2m6525c8jf7cvvpab4k.png)
where: 25.004 ≅ 25
![(r_(2))^(2)=25](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dep6k8mih52yc1l71ahorquet2qn24mi22.png)
![r_(2)=√(25)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wm5w124x39orlo4w4oaej5gaug7pz72ft9.png)
![r_(2)=5\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/y7kq98qgyulxq3vim24cgpehggn8od8e7z.png)
Therefore; the radius of the circle is 5 cm.