72.6k views
4 votes
The length of a swimming pool is 3 feet longer than it’s width. The swimming pool is surrounded by a deck that is 2 feet wide and has an area of 116 square feet. Find the dimensions of the pool

User Nathalie
by
4.6k points

1 Answer

4 votes

Answer:

The Length of swimming pool is 8.35 feet

The width of swimming pool is 5.35 feet

Explanation:

Given as :

The length of swimming pool is 3 feet longer that its width

Let The width of swimming pool = w feet

So, The Length of swimming pool = L = (w + 3) feet

Now, The swimming pool is surrounded by deck of 2 feet wide

The width of deck = w' = w + 2 + 2 = (w + 4) feet

The area of deck = 116 feet²

The length of deck = L' = L + 2 + 2 = (L + 4) feet

So, L' = (w + 3 + 4) feet

I.e L' = (w + 7) feet

∵ The area of deck = 116 feet²

So , L' × w' = 116 feet²

(w + 7)× (w + 4) = 116

Or, w² + 4 w + 7 w + 28 = 116

Or, w² + 11 w - 88 = 0

Solving the quadratic equation as

ax² + bx + c = 0

So, w =
\frac{-b\pm \sqrt{b^(2)-4* a* c}}{2* a}

Or, w =
\frac{-11\pm \sqrt{11^(2)-4* 1* (-88)}}{2* 1}

Or, w =
(-11\pm √(473))/(2)

or, w =
(-11\pm 21.7)/(2)

or, w = 5.35 , -16.35

The width of swimming pool = w = 5.35 feet

The Length of swimming pool = L = (5.35 + 3) feet = 8.35 feet

Hence, The Length of swimming pool is 8.35 feet

And The width of swimming pool is 5.35 feet

Answer

User Shadow Fiend
by
5.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.