Answer:
The Length of swimming pool is 8.35 feet
The width of swimming pool is 5.35 feet
Explanation:
Given as :
The length of swimming pool is 3 feet longer that its width
Let The width of swimming pool = w feet
So, The Length of swimming pool = L = (w + 3) feet
Now, The swimming pool is surrounded by deck of 2 feet wide
The width of deck = w' = w + 2 + 2 = (w + 4) feet
The area of deck = 116 feet²
The length of deck = L' = L + 2 + 2 = (L + 4) feet
So, L' = (w + 3 + 4) feet
I.e L' = (w + 7) feet
∵ The area of deck = 116 feet²
So , L' × w' = 116 feet²
(w + 7)× (w + 4) = 116
Or, w² + 4 w + 7 w + 28 = 116
Or, w² + 11 w - 88 = 0
Solving the quadratic equation as
ax² + bx + c = 0
So, w =
![\frac{-b\pm \sqrt{b^(2)-4* a* c}}{2* a}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ysr0j6p74ax5hfnmjavn12wvn2lsaucgwo.png)
Or, w =
![\frac{-11\pm \sqrt{11^(2)-4* 1* (-88)}}{2* 1}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/q8q0j4fjc844x5b24w9b4vbl8jfdbn89re.png)
Or, w =
![(-11\pm √(473))/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5lrwm1tum87nk9nnpcebem0venvuf5nn5x.png)
or, w =
![(-11\pm 21.7)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/h82m0r8f9ydfl3732hmnrmm0o9t97vgxmf.png)
or, w = 5.35 , -16.35
The width of swimming pool = w = 5.35 feet
The Length of swimming pool = L = (5.35 + 3) feet = 8.35 feet
Hence, The Length of swimming pool is 8.35 feet
And The width of swimming pool is 5.35 feet
Answer