Answer: 0.0035
Explanation:
Given : The readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees C.
i.e.
and
Let x denotes the readings on thermometers.
Then, the probability that a randomly selected thermometer reads greater than 2.17 will be :_
![P(X>2.7)=1-P(\xleq2.7)\\\\=1-P((x-\mu)/(\sigma)\leq(2.7-0)/(1))\\\\=1-P(z\leq2.7)\ \ [\because\ z=(x-\mu)/(\sigma)]\\\\=1-0.9965\ \ [\text{By z-table}]\ \\\\=0.0035](https://img.qammunity.org/2020/formulas/mathematics/college/i0e2z9ywblnuvlo7uvybtofuw15bpxa0tc.png)
Hence, the probability that a randomly selected thermometer reads greater than 2.17 = 0.0035
The required region is attached below .