Question

What is the average rate of change of the function f(x)=120(.1)^x from x=0 to x=2

Answer 1

- 59.4

Explanation:

The given function is
`f(x) = 120(0.1)^(x)`

Therefore, at x = 0,
`f(0) = 120(0.1)^(0) = 120` and

at x = 2,
`f(2) = 120(0.1)^(2) = 1.2`

Hence, the average rate of change of the given function from x = 0 to x = 2 will be

`(f(2) - f(0))/(2 - 0)`

=
`(1.2 - 120)/(2 - 0)`

= - 59.4 (Answer)