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A bowling ball of mass 5.8 kg moves in a

straight line at 1.59 m/s.
How fast must a Ping-Pong ball of mass
1.528 g move in a straight line so that the two
balls have the same momentum?
Answer in units of m/s.

1 Answer

3 votes

Answer:

Velocity of the ping pong ball must be = V2= 6,035.34m/s

Step-by-step explanation:

M1= momentum of the bowling ball

m1 = mass of the bowling ball= 5.8kg

v1= velocity of the bowling ball= 1.59m/s

M2= momentum of the ping pong ball

m2= mass of the ping pong ball= 1.528 g/1000= 0.001528kg

v2= velocity of the ping pong ball

Momentum of the bowling ball= M1= m1v1= 5.8* 1.59= 9.222 kg-m/s

Momentum of the ping pong ball = M2= M1= m2v2

= 0.001528 *v2= 9.222

v2= 9.222/0.001528= 6,035.34 m/s

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