Question

Unpolarized light with intensity S is incident on a series of polarizing sheets. The first sheet has its transmission axis oriented at 0°. A second polarizer has its transmission axis oriented at 45° and a third polarizer oriented with its axis at 90°. Determine the fraction of light intensity exiting the third sheet with and without the second sheet present.

Answer 1

Step-by-step explanation:

Given

Initial Intensity of light is S

when an un-polarized light is Passed through a Polarizer then its intensity reduced to half.

When it is passed through a second Polarizer with its transmission axis
`\theat =45^(\circ)`

`S_1=S_0\cos ^2\theta`

here
`S_0=(S)/(2)`

`S_1=(S)/(2)* (1)/((√(2))^2)`

`S_1=(S)/(4)`

When it is passed through third Polarizer with its axis
`90^(\circ)` to first but
`\theta =45^(\circ)` to second thus
`S_2`

`S_2=S_0\cos ^2\theta`

`S_2=(S)/(4)* (1)/(2)`

`S_2=(S)/(8)`

When middle sheet is absent then Final Intensity will be zero