Question

a bicycle accelerates at 1 m/s² from an initial velocity of 4 m/s² for 10s. Find the distance moved by it during this interval of time?​

Answer 1

90 m

Step-by-step explanation:

Acceleration,
`a=\frac {v-u}{t}` where v and u are final and initial velocities respectively, t is the time taken

Substituting
`1 m/s^(2)` for a, 4 m/s for u and 10 s for t then

1*10=v-4

v=14 m/s

From kinematic equations

`v^(2)=u^(2)+2as`

Making s the subject then

`s=\frac {v^(2)-u^(2)}{2a}=\frac {14^(2)-4^(2)}{2* 1}=90 m`