Answer:
Cost of a coffee is $2.5 and cost of a latte is $4.25.
Explanation:
Let cost of 1 coffee be 'c' and cost of 1 latte be 'l' dollars.
Given:
4 coffees and 12 lattes cost $61.
12 coffees and 7 lattes cost $59.75.
∵ 1 coffee cost =

∴ 4 coffees cost =
and 12 coffee cost =

∵ 1 latte cost =

∴ 12 lattes cost =
and 7 lattes cost =

Now, as per question:

Now, multiplying equation (1) by -3 and adding the result to equation (2). This gives,

Now, plug in the value of 'l' in equation 1 to solve for 'c'. This gives,

Therefore, cost of a coffee is $2.5 and cost of a latte is $4.25.