Question

I know that the balloon weighs about 210 kg. The balloon itself weighs 7/9 out of this. The rest of the weight is composed of sand sacks and empty gas tanks. If the weight of the gas tank is 1/6 of that of the sacks, how much do the tanks and the sacks weigh each?

Answer 1

Gas Tanks weighs 20/3kg i.e. 6.67kg while Sacks weighs 40kg

Explanation:

Total weight = 210kg

`Balloon Weight = (7)/(9) *210\\Balloon Weight = (490)/(3)kg`

Balloon Weight = 163.33kg

Remaining Weight = 210 - (490/3)

`=(630-490)/(3)`

=46.67kg

Let the weight of Gas tank = g

Let the weight of Sacks = s

This remaining weight comprises of weight of Sacks and Gas Tanks.

i.e.

g+s = 140/3 = 46.67

As given that,

`g=(1)/(6)*s`

So,

`s((1)/(6)+1) = (140)/(3)`

`s((7)/(6) ) = (140)/(7)`

s=40kg

As provided

Now to find g:

g+s = 140/3

`g=(140)/(3)-s\\=(140)/(3) -40\\<strong>=(20)/(3)kg\\=6.67kg</strong>`