Question

A concentration cell is constructed by using the same half-reaction for both the cathode and anode. What is the cell potential E at 298K for a concentration cell that combines a silver cathode in contact with 0.10 M silver nitrate and a silver anode in contact with 0.00003 M silver nitrate? (Eored = +0.80 V for Ag/Ag+)

Answer 1

`E^o_(cell)=0\ V`

Step-by-step explanation:

Concentration of silver cathode =
`0.10\ M \ AgNO_3.`

Concentration of silver anode =
`0.00003\ M \ AgNO_3.`

It is given that ,
`E^o_(red)=+0.80 \ V.`

We know in a standard cell,

Reduction:

Oxidation :
`Ag^++e^-->Ag  \  \  \ \ \ \ \ E^o=+0.80\ V \\ Ag\ ->Ag^++e^-\ \ \ \ \ \  E^o=-0.80\ V`

We know,
`E^o_(cell)=E_(red)+ E_(ox)\\=-0.80\ +0.80 \ V\\=0\ V.`

Therefore,
`E^o_(cell)=0\ V`

Hence this is the required solution.