Answer:
The speaker should be placed at either 4.111 m or 7.888 m
Step-by-step explanation:
We have given frequency f = 90 Hz
and velocity of the sound v = 340 m /sec
So wavelength
![\lambda =(v)/(f)=(340)/(90)=3.777m](https://img.qammunity.org/2020/formulas/physics/college/uil1fpu4ur7bg7p15u4oypubr56gcriuhj.png)
Here path difference will be equal to wavelength
So
![s_1-s_2=\pm (\lambda )/(2)=\pm (3.777)/(2)=\pm 1.888](https://img.qammunity.org/2020/formulas/physics/college/y76rlmz7umpjmlgxek9bich9u6y83ydvcq.png)
![s_1-6=\pm 1.888](https://img.qammunity.org/2020/formulas/physics/college/w9f1ht29s1bd99sd51uc70xwx6mtdar1ib.png)
![s_1=4.111m,\ 7.888m](https://img.qammunity.org/2020/formulas/physics/college/30bxrtq671y9qtchgn3vpfxe05xjno1thf.png)
So the speaker should be placed at either 4.111 m or 7.888 m