Question

Which is true about the self-induced emf of an inductor?

It is a fixed value, depending on only the geometry of the device.

It depends on the amount of current through the inductor.

It depends on the rate of dissipation.

It depends on the rate at which the current through it is changing.

Answer 1

It depends on the rate at which the current through it is changing.

Step-by-step explanation:

As per the Faraday's law, the induced emf is given by :

`\epsilon=-L(di)/(dt)`

Where

L is the inductance of the inductor

`(di)/(dt)` is the rate of change of current

So, the self-induced emf of an inductor depends on the rate at which the current through it is changing. Hence, the correct option is (d).