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At a given temperature, the elementary reaction A − ⇀ ↽ − B , in the forward direction, is first order in A with a rate constant of 0.0340 s − 1 . The reverse reaction is first order in B and the rate constant is 0.0740 s − 1 . What is the value of the equilibrium constant for the reaction A − ⇀ ↽ − B at this temperature?

User Sajid Zeb
by
7.7k points

1 Answer

4 votes

Answer:

0.4595 is the value of the equilibrium constant for the reaction.

Step-by-step explanation:

A ⇆ B

The forward direction, is first order in A with a rate constant = K =
0.0340 s^(-1)

The rate of forward reaction = R


R=K[A]

The backward direction, is first order in A with a rate constant = K' =
0.0740 s^(-1)

The rate of backward reaction = R'


R'=K'[B]

At equilibrium rate of forward reaction are equal to the rate of backward reaction.

R = R'


K[A]=K'[B]


K_(eq)=([B])/([A])=(K)/(K')=(0.0340 s^(-1))/(0.0740 s^(-1))=0.4595

0.4595 is the value of the equilibrium constant for the reaction.

User Craig Graham
by
8.3k points
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